JS实现的按钮点击颜色切换功能示例
(编辑:jimmy 日期: 2024/11/20 浏览:3 次 )
本文实例讲述了JS实现的按钮点击颜色切换功能。分享给大家供大家参考,具体如下:
先来看看运行效果:
具体代码如下:
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>www.jb51.net 点击切换按钮颜色</title> </head> <body> <button id="btn1" onclick="btn(1)">按钮1</button> <button id="btn2" onclick="btn(2)">按钮2</button> <button id="btn3" onclick="btn(3)">按钮3</button> <script> //设置背景颜色 //如果设置参数函数会节省函数数量吧 //设置flag+参数函数 flag = "btn1"; function btn1(){ document.getElementById("btn2").style.color = "black"; document.getElementById("btn3").style.color = "black"; document.getElementById("btn1").style.color = "red"; } function btn2(){ document.getElementById("btn1").style.color = "black"; document.getElementById("btn2").style.color = "red"; document.getElementById("btn3").style.color = "black"; } function btn3(){ document.getElementById("btn1").style.color = "black"; document.getElementById("btn2").style.color = "black"; document.getElementById("btn3").style.color = "red"; } function btn(num){ if(num == 1){ document.getElementById(flag).style.color = "black"; document.getElementById(flag).style.backgroundColor = "white"; document.getElementById("btn1").style.color = "red"; document.getElementById("btn1").style.backgroundColor = "blue"; flag = "btn1"; } if(num == 2){ document.getElementById(flag).style.color = "black"; document.getElementById(flag).style.backgroundColor = "white"; document.getElementById("btn2").style.color = "red"; document.getElementById("btn2").style.backgroundColor = "blue"; flag = "btn2"; } if(num == 3){ document.getElementById(flag).style.color = "black"; document.getElementById(flag).style.backgroundColor = "white"; document.getElementById("btn3").style.color = "red"; document.getElementById("btn3").style.backgroundColor = "blue"; flag = "btn3"; } } </script> </body> </html>
更多关于JavaScript相关内容感兴趣的读者可查看本站专题:《JavaScript切换特效与技巧总结》、《JavaScript遍历算法与技巧总结》、《JavaScript查找算法技巧总结》、《JavaScript错误与调试技巧总结》、《JavaScript数据结构与算法技巧总结》及《JavaScript数学运算用法总结》
希望本文所述对大家JavaScript程序设计有所帮助。
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